2x^2+x=11.88

Solution for 2x^2+x=11.88 equation:

2x^2+x=11.88

We move all terms to the left:

2x^2+x-(11.88)=0

We add all the numbers together, and all the variables

2x^2+x-11.88=0

a = 2; b = 1; c = -11.88;
Δ = b2-4ac
Δ = 12-4·2·(-11.88)
Δ = 96.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{96.04}}{2*2}=\frac{-1-\sqrt{96.04}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{96.04}}{2*2}=\frac{-1+\sqrt{96.04}}{4}
$